Web2 dec. 2024 · If ∫ 1/√ (1+x)-√x .dx = k/3 ,x ∈ [0, 1] then k is equal to (a) √2 (2√2–2) (b) √2/3 (2–2√2) - Sarthaks eConnect Largest Online Education Community If ∫ 1/√ (1+x)-√x .dx = k/3 ,x ∈ [0, 1] then k is equal to (a) √2 (2√2–2) (b) √2/3 (2–2√2) ← Prev Question Next Question → 0 votes 107 views http://math.stanford.edu/~ksound/Math171S10/Hw7Sol_171.pdf
if ∫(3x+4/x3-2x-4)dx =log x-2 +k logf(x)+c, then - Tardigrade
WebClick here👆to get an answer to your question ️ If int0^kcosx/1 + sin^2xdx = pi/4 then k = ? Solve Study Textbooks Guides. Join / Login >> Class 12 >> Maths >> Integrals >> … Web4dx = 4x = 4(2) 4( 2) = 16 or draw the graph of the function f(x) = 4 and use the formula for the area of a rectangle 2 2 ... dx = 0: Going from 2 to 5 and then from 5 back to 2 yields no net movement. Rearranging the above gives Z 2 5 f(x)dx = Z 5 2 f(x)dx = 7: 5.Compute the following inde nite integral Z 2x+ x3 p x dx: hawaiian airlines to las vegas flights
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WebThe value of the integral 1∫ 2 ex (logex + xx+1)dx is WBJEE 2013 3. If f (x) = ∫ 1x 4 −t2 dt, then real roots of the equation x− f ′(x) = 0 are J & K CET 2012 4. If f (x) = 2x∫ sinx … Web6 jul. 2016 · Use the substitution x = tanu and 1 +tan2u = sec2u .. The limits become π 2 and ∞, and dx = sec2u du. The given integral reduces to the form ∫usinucosudu = 1 2 ∫usin2udu = ( − 1 4)∫ud(cos2u) = − 1 4[ucos2u −∫cos2udu], between the limits 0 and π 2 =. ( − 1 4)( π 2)( − 1) + 1 4 [1 2sin2u], between the limits = π 8 +0 = π 8 - Answer link Eddie WebIf ∫ 0 a 1 4 + x 2 d x = π 8 , find the value of a. Advertisement Remove all ads Solution given that ∫ 0 a 1 4 + x 2 d x = π 8 We need to find the value of a. L e t I = ∫ 0 a 1 4 + x 2 d x = π 8 T h u s, I = 1 2 ( tan - 1 ( x 2)) 0 a = π 8 ⇒ 1 2 tan - 1 ( a 2) = π 8 ⇒ tan - 1 ( a 2) = π 4 ⇒ a 2 = tan ( π 4) ⇒ a 2 = 1 a = 2 hawaiian airlines toll free phone number